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Author: rmhj Big gold star, 5000 posts Old School Fool Add to my Favorite Fools Ignore this person (you won't see their posts anymore) Number: of 5889  
Subject: Re: A (complex) puzzle Date: 9/23/2011 3:06 PM
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LorenCobb: Not in Gnu Fortran, I believe. The Fortran call log(x), where x is complex, generates a complex answer (the principal value of the complex logarithm). These doc files

say as much, though they do not specify what would happen if the log function is called on a negative constant.

That is what I'd expect, FORTRAN having had COMPLEX data types since day IV (if not earlier). However, the argument is a REAL (or integer?), and I've long since forgotten FORTRAN's type conversion and promotion rules (and I don't know what they say about evaluation of constants at compile time). Unlike C, they're probably quite strict (ISTR that parentheses are inviolate in FORTRAN).

If you're angling to do all this in complex arithmetic, then the result probably comes out very weird if you apply Euler's identity, e^(i(theta)) = cos(theta) = i*sin(theta) after doing the original exponent rearrangement. If you do, then you get the ln(-4) ~= 1.386... + pi*i. Multiply by 3/2 (2.07944... + 4.7123...i) and exponentiate, and the result is -8i.

But I think most of us would understand any of these answers (domain error, 8, -8i).

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