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shuksan77: "This may require some handicap geekery...

I just played in a handicapped scramble. On my team were 14, 15, 16, and 1. Playing best ball we also had a team handicap, which was 8. The club pro adds up all the handicaps and divides by 8 to get the team HCP. I think we came in at a net 62: 70 for the scramble less team HCP."

What best ball? 46/4 = 11.5; where did the 8 come from?

"The almost-winning team was the pro, his son, and two others. Their handicaps were 2, 10, 10, and 26 with a team HCP of 6. I think they had a net 54."

48/4 = 12, not 6. I do not currently follow.

The only rules were that each person has to use two drives and two second shots per side.

"Now it seems to me this is not even, despite the handicaps."

I agree, but I am not exactly certain that I can elaborate. The two shots and two second shots per side evens things a little, but assuming a standard nine, 2 par 3s, 2 par 5s and 5 par 4s, there are only 7 second shots per side, unless you count puts on the par 3s.

How would yoru pro handicap a 1, 2, 3 and 30? 36/4 = 9 but a 1, 2 and 3 should be several shots under par per side. The 30 might drag the group a little but assuming decent par 3 tee shots and unreachable par 5s, you can probably find two tee shots. I am still curious about the second shot requirement.

I do not have any scramble handicap suggestions handy, but I do agree with you.

Regards, JAFO
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