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Subject: Re: Probability problem  Date: 9/8/2020 9:31 AM  
Author: bighairymike  Number: 5995 of 6013  
There are 3 dice in a bag: 6sided, 12sided and 20sided. We pick one die at random, roll it, and it gives us a number N. What's the probability that when we pick another die and roll it, we'll get a number smaller than N, if N = 4?  OK, I'll take a crack at it.... Possible scenarios. 1. pull 6 side first which shows the 4, leaves 32 (12+20) possible outcomes in the bag. 2. pull 12 side first which shows the 4, leaves 26 (6+20) possible outcomes in the bag. 3. pull 20 side first which shows the 4, leaves 18 (6+12) possible outcomes in the bag. So there a universe of 76 total outcomes. With two dice left in the bag, there are three outcomes less than 4 on each dice, so 6 potential outcomes less than 4. With three scenarios, each having six potential outcomes less than 4, gives 18 total outcomes less than 4. 18/76 = 0.236842 

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