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No. of Recommendations: 0
you guys did a great job of it.

here is the solution, a discussion can follow later
pirate
1 2 3 4 5 6 7 8 9 10

1000 0 (and hope)
0 0 1000
1 1 0 998
0/2 2/0 1 0 997
0/2/2 2/0/2 2/2/0 1 0 995
two to any 2 of the 1st 4 1 0 995
two to any 3 of the 1st 5 1 0 993
two to any 3 of the 1st 6 1 0 993
two to any 4 of the first 7 1 0 991


i just find this a terrific deduction problem with respect to working the solution backwards to front.

tr
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